15p^2-p-40=0

Solution for 15p^2-p-40=0 equation:

15p^2-p-40=0

We add all the numbers together, and all the variables

15p^2-1p-40=0

a = 15; b = -1; c = -40;
Δ = b2-4ac
Δ = -12-4·15·(-40)
Δ = 2401
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2401}=49$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-49}{2*15}=\frac{-48}{30}
=-1+3/5
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+49}{2*15}=\frac{50}{30}
=1+2/3
$